what will thie do filePattern = [imagesFolder, '\*.*'];
3 ビュー (過去 30 日間)
古いコメントを表示
what will this statement will do ?
filePattern = [imagesFolder, '\*.*'];
0 件のコメント
採用された回答
KSSV
2016 年 11 月 18 日
Folder = 'path of the file';
filePattern = [Folder, '\*.*'];
It concatenates/ joins the path Folder and '\*.*'. Now filepattern can be used to get the details of the files present in the given path of all possible extensions. It will be helpfull to get the files present in the folder.
F = dir(filePattern) ;
F will be a stricture with information of files in the folder.
0 件のコメント
その他の回答 (0 件)
参考
カテゴリ
Help Center および File Exchange で Read, Write, and Modify Image についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!