Step func at time different then t = 0

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Alexandru Miculescu
Alexandru Miculescu 2016 年 11 月 15 日
回答済み: Arkadiy Turevskiy 2016 年 12 月 6 日
Hi. I want to plot the step response of (10*g0) at t = 5. How can i do that? Thank you!
if true
clc;
G = tf([10],[10 1]);
H = 1;
g0 = feedback(G,H)
Kp = 2.4;
Ki = 1.5;
Kd = 0;
C = pid(Kp,Ki,Kd);
g0 = feedback(C*G,H);
step(10*g0);
end
  1 件のコメント
Akash Kalghatgi
Akash Kalghatgi 2016 年 11 月 15 日
Provide a phase shift, like (10*g0+ "phase shift") I don't know the exact syntax for MATLAB, so you've got to search it. Type 'help (function name)' in command window for more information about any function

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回答 (1 件)

Arkadiy Turevskiy
Arkadiy Turevskiy 2016 年 12 月 6 日
The question is not clear. Does a. Step happens at 0 secs and you want to show the response at 5 secs? or b. Step happens at 5 secs?
Assuming you ask about the latter:
[Y,T]=step(10*g0);
plot(T+5,Y)

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