I want to copy the rows of G1 to G2 in inner for loop but error occurs , please help

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Junaid Khan
Junaid Khan 2016 年 11 月 13 日
編集済み: Walter Roberson 2016 年 11 月 14 日
G1 = [1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1;
0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1;
0 0 0 0 1 1 1 1 0 0 0 0 1 1 1 1;
0 0 1 1 0 0 1 1 0 0 1 1 0 0 1 1;
0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1;
0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1;
0 0 0 0 0 0 0 0 0 0 1 1 0 0 1 1;
0 0 0 0 0 0 1 1 0 0 0 0 0 0 1 1;
0 0 0 0 0 0 0 0 0 1 0 1 0 1 0 1;
0 0 0 0 0 1 0 1 0 0 0 0 0 1 0 1;
0 0 0 1 0 0 0 1 0 0 0 1 0 0 0 1];
m=4;
r=4;
k=0;
n=2^m;
k=15;
for a=r:-1:2
M=factorial(m)/(factorial(m-a)*factorial(a));
G2 = zeros(M,n);
for o=1:1:M
G2(o,:) = G1(k,:);
k=k-1;
end
end

回答 (1 件)

Daniel kiracofe
Daniel kiracofe 2016 年 11 月 13 日
the first time through the loops, k = 15. but size(G1) is 11x16. So the first time you are effectively doing
G2(o,:) = G1(15,:)
which doesn't work. Maybe you meant this instead?
G2(:, o) = G1(:,15)
  2 件のコメント
Daniel kiracofe
Daniel kiracofe 2016 年 11 月 13 日
That doesn't change anything about my previous comment. at the conclusion of this section of the code
for i=1:r k= k+factorial(m)/(factorial(m-i)*factorial(i)) end
the variable k has the value 15. And G1 has size 11x16 = 11 rows and 16 columns.. So G1(k,:) is asking to access the 15th row of a matrix that has only 11 rows. You can't copy a row that doesn't exist.

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