Why won't my rlocus function work

6 ビュー (過去 30 日間)
John Smith
John Smith 2016 年 11 月 3 日
回答済み: Star Strider 2016 年 11 月 3 日
close all; clc; clear
% Q1
A=[0 1 0 0; -4 -56 4 56; 0 0 0 1; 31.25 437.5 -62.5 -437.5];
B=[0 0; 1 0; 0 0; 0 31.25];
C=[1 0 -1 0];
D=[0 0];
[n1,d1]=ss2tf(A,B,C,D,1) % nominator and denominator of P
[n2,d2]=ss2tf(A,B,C,D,2) % nominator and denominator of F
P=tf(n1,d1) % transfer function of P=Y/U
F=tf(n2,d2) % transfer function of F=Y/W
% Q2
D=F/P % transfer function of D
Dmin=minreal(D) % simplified D
% Q3
P_poles=pole(P) % poles of plant P
%Q4
pole_far=P_poles(1)
s=tf('s');
P_s=minreal(((pole_far-s)/(pole_far))*P)
%Q5
rlocus(P_s)
%Q6
z1=-1+(-4)^0.5;
z2=-1-(-4)^0.5;
p1=-20;
p2=-50;
N=(P_s*(s-z1)*(s-z2))/((s-p1)*(s-p2));
figure
rlocus(N)
axis([-4 0.5 -6 6])
%Q7
[k,poles]=rlocfind(N);
%Q8
C=k*(s-z1)*(s-z2)/((s-p1)*(s-p2));
H=Dmin*feedback(P,C);
step(0.2*H)
if true
% code
end
Also H isnt producing anything, where have I gone wrong?

回答 (1 件)

Star Strider
Star Strider 2016 年 11 月 3 日
The numerator of ‘N’ is complex, although the imaginary parts are vanishingly small (on the order of approximation error), so you can safely delete them. Add the ‘N.numerator’ assignment to your code just after the initial ‘N’ assignment, and it works (at least as far as I’ve tested it):
N=(P_s*(s-z1)*(s-z2))/((s-p1)*(s-p2));
N.numerator = real(N.numerator{:})); % <— ADD THIS ASSIGNMENT

カテゴリ

Help Center および File ExchangeClassical Control Design についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by