making the string into a matrix

N=length(str);
count=1;
for k=1:N
m=str2double(str(k));
if isnan(m)==0
str(count)=k;
count=count+1;
numbers = cell2mat(sscanf((str),'k'))
disp(m)
end
end
this is currently the code I have "str" is the number inputted by the user, however my code isn't working. If the user were to input: 1234509876 then I would want the outcome to be numbers=[1,2,3,4,5,0,9,8,7,6]; what can I do?

1 件のコメント

Walter Roberson
Walter Roberson 2016 年 10 月 27 日
編集済み: Walter Roberson 2016 年 10 月 27 日
How do you intend to hand the case where the user asks for 0 as the first entry? For example if the user asks for 007 then how do you intend to tell the difference compared to if they had just asked for 7 ?

回答 (1 件)

KSSV
KSSV 2016 年 10 月 27 日

0 投票

n = 1234509876 ;
iwant = sscanf( sprintf( '%u', n ), '%1d' )'

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