please know that the value of x and y is different on every call, it takes different values of x and y every time it's called.
creating a function for my repeating computation
1 回表示 (過去 30 日間)
古いコメントを表示
I want to create a function for the following set of repeated computations i will be performing in my work.
d = ((x*b) - y).^2;
test = sum (d(:))/1000;
Your help is much appreciated.
回答 (1 件)
Walter Roberson
2016 年 10 月 18 日
test = @(b, x, y) sum( reshape( (x*b - y).^2, [], 1) ) / 1000;
Now
result = test(b, x, y); %a call to the function
Question: do there happen to be exactly 1000 elements in y, so it is computing a mean? If so then
test = @(b, x, y) mean2( (x*b - y).^2 ); %if you have the image processing toolbox
test = @(b, x, y) mean( reshape( (x*b - y).^2, [], 1) ); %if you do not have image processing
For some shapes of x and b and y, it would be possible to use (:) instead of reshape()
0 件のコメント
参考
カテゴリ
Help Center および File Exchange で Image Processing Toolbox についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!