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How to find time constants from given 2+ order transfer function?

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shrivardhan  suryawanshi
shrivardhan suryawanshi 2016 年 10 月 16 日
編集済み: Gerard Nagle 2023 年 4 月 29 日
I have a transfer function let us take for e.g k/(100*s^2+20*s+1).In this TF I want to access the denominator as k/(10*s+1)(10*s+1) in such a way that algorithm will return tau1=10,tau2=10.How to get it?

回答 (1 件)

David Wilson
David Wilson 2020 年 8 月 26 日
If you just want to display the transfer function in time-constant form, you can do the following:
s = tf('s');
k = 45; % anyhting
G = k/(100*s^2+20*s+1) % expanded polynomial form
[z,p,k] = zpkdata(G)
G1 = zpk(z,p,k,'DisplayFormat','timeconstant')
If you want access to the time constants, use damp.m
damp(G)
[w, zeta, p] = damp(G)
tau = 1./w
I',m assuming you have a stable TF. Check with isstable.
  1 件のコメント
Gerard Nagle
Gerard Nagle 2023 年 4 月 29 日
編集済み: Gerard Nagle 2023 年 4 月 29 日
Was trying for hours to get a nice format and do this using my own code. Should have read the documentation closer. Thanks for the answer

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