Error: The variable voltages1 in a parfor cannot be classified.
1 回表示 (過去 30 日間)
古いコメントを表示
Hello,this is my code.
It is not runing because "The variable voltages1 in a parfor cannot be classified." Why?
voltages1 = num2cell(zeros(1,256),1);
voltages2 = voltages1;
parfor i=1:8
inputVoltage1 =readVoltage(a,'A0');
inputVoltage2 =readVoltage(a,'A5');
voltages1{256} = inputVoltage1;
voltages2{256} = inputVoltage2;
subplot(2,1,1) ;
[ax,h1,h2] = plotyy(times,voltages1{:},times,voltages2{:});
%axis(ax(1),[0 1 0 5]);
%axis(ax(2),[0 1 0 5]);
set(h1,'xdata',times,'ydata',voltages1{:});
set(h2,'xdata',times,'ydata',voltages2{:});
set(get(ax(1),'Ylabel'),'String','I Channel');
set(get(ax(2),'Ylabel'),'String','Q Channel');
title('Time Domain');
set(h1,'Linewidth',2);
set(h2,'Linewidth',2);
drawnow update;
voltages1{1:255} = voltages1{2:256};
voltages2{1:255} = voltages2{2:256};
end
0 件のコメント
採用された回答
Marc Jakobi
2016 年 10 月 4 日
The problem is the line
voltages1{256} = inputVoltage1;
You cannot set a fixed index of an array or a matrix in a parfor loop, since multiple parallel instances of the loop will conflict with each other, trying to set voltages1{256} to different values at the same time.
4 件のコメント
Marc Jakobi
2016 年 10 月 5 日
I think you want to use for instead of parfor. parfor is used for parallel computing and doesn't make much sense when generating figures.
その他の回答 (1 件)
参考
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!