フィルターのクリア

Comparing values in an array to a range

5 ビュー (過去 30 日間)
Matlabhelp
Matlabhelp 2016 年 9 月 28 日
コメント済み: Rik 2020 年 8 月 25 日
Hello
I'm wondering how to compare my values in an array ( 20x20) to a certain range, if found within that certain range will display the given value for the range. For example the array consists of numbers between ( 1 - 5, inclusive of decimal numbers such as 1.5, 0.5, 3.5 etc ) i have 5 given ranges, one being 0.5 - 1, and if that value is found between those numbers it will display a 1 for that number. And if it was found between 1.1-1.6 it will display a 2. I want to be able to compare each number to each range in one short code but don't know how
  1 件のコメント
Rik
Rik 2020 年 8 月 25 日
Copy of the question in case he deletes this one as well:
Comparing values in an array to a range
Hello
I'm wondering how to compare my values in an array ( 20x20) to a certain range, if found within that certain range will display the given value for the range. For example the array consists of numbers between ( 1 - 5, inclusive of decimal numbers such as 1.5, 0.5, 3.5 etc ) i have 5 given ranges, one being 0.5 - 1, and if that value is found between those numbers it will display a 1 for that number. And if it was found between 1.1-1.6 it will display a 2. I want to be able to compare each number to each range in one short code but don't know how

サインインしてコメントする。

採用された回答

Andrei Bobrov
Andrei Bobrov 2016 年 9 月 28 日
編集済み: Andrei Bobrov 2016 年 9 月 28 日
a = rand(20,20)*5;
edges = [.5,1,1.1,1.6];
ii = discretize(a,edges);% [~,ii] = histc(a,edges) - if MATLAB older then R2014b
w = [1 0 2 ];
ii(ii>0) = w(ii(ii>0));
Please read about discretize and histcounts.
OR
t1 = a >= .5 & a < 1;
t2 = a >=1.1 & a < 1.6;
ii = t1 + 2*t2;
  1 件のコメント
Matlabhelp
Matlabhelp 2016 年 9 月 28 日
cheers

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeShifting and Sorting Matrices についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by