Write a function called digit_counter that takes the name of a text file as input and returns the number of digits (i.e., any of the characters, 0-to-9) that the file contains. If there is a problem opening the file, the function returns -1

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function[c]=digit_counter(filename)
fid=fopen(filename,'rt');
if fid<0
error('error opening file %s', filename);
end
A = char(fread(fid,inf)).';
c=length(A);
fclose(fid);
end

回答 (2 件)

Walter Roberson
Walter Roberson 2016 年 9 月 23 日
Your code returns the number of bytes in the file. The requirements are that it return the number of digits in the file -- that is, the total number of occurrences of any of the characters '0', '1', '2', '3', '4', '5', '6', '7', '8', or '9'
  2 件のコメント
Kapil Dhanwani
Kapil Dhanwani 2016 年 9 月 23 日
Yes I want digits only...no alphabets and no space so what changes I should make
Walter Roberson
Walter Roberson 2016 年 9 月 23 日
Hint:
if A(idx) == '0'
digit0 = digit0 + 1;
elseif ....

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Srishti Saha
Srishti Saha 2018 年 5 月 13 日
A simple function as this would work:
function n = digit_counter(fname)
n = -1;
fid = fopen(fname,'r');
if fid >= 0
n = sum(isstrprop(fread(fid,inf,'char=>char'),'digit'));
fclose(fid);
end
end

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