Moving a dot at a constant velocity in a circular path in MATLAB
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VINAY KUMAR REDDY MEDAPATI
2016 年 9 月 13 日
編集済み: Maryam Naveed
2019 年 4 月 24 日
Hello, I want to present a dot in a rectangular field and make it move in the field at a constant velocity in a circular path (the position of the dot has to be known with respect to time). Additionally I want to manipulate the initial position in which it will be presented. Can anyone help me ?
2 件のコメント
James Tursa
2016 年 9 月 13 日
Have you written any code so far? A simple formulation something like the following would get you the position of the dot for time t:
pos = [x0,y0] + r*[cos(theta0 + thetadot*t),sin(theta0 + thetadot*t)];
VINAY KUMAR REDDY MEDAPATI
2016 年 9 月 13 日
編集済み: VINAY KUMAR REDDY MEDAPATI
2016 年 9 月 13 日
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Star Strider
2016 年 9 月 13 日
See if this does what you want:
crc = @(r,p,a) [r*cosd(a + p); r*sind(a + p)];
t = linspace(0, 360, 361); % Time
init_pos = 25; % Initial Position (°)
radius = 1.2;
locus = crc(radius, init_pos, t);
figure(1)
for k1 = 2:length(t)
plot(locus(1,k1), locus(2,k1), 'gp')
axis([-1.5 1.5 -1.5 1.5])
grid
axis square
drawnow
end
9 件のコメント
Star Strider
2016 年 9 月 15 日
My pleasure.
It would be entirely different for square and zig-zag paths. Plotting a square and zig-zag paths I will leave to you. You may be able to adapt the circle-plotting algorithm to the square by using the cotangent function to change the radius to a straight line, considering your ‘requirements’ and constraints. A sawtooth function would be relatively easy to program, but a true zig-zag more difficult, especially if you wanted the radius of the circle to be a zig-zag.
sawtooth = @(a,p) rem(a,p).*(rem(a,p)<p);
figure(2)
plot(t, sawtooth(t,45))
grid
Maryam Naveed
2019 年 4 月 24 日
編集済み: Maryam Naveed
2019 年 4 月 24 日
Can you further explain me this code?Actually i want 100 points that are arranged in 10 rows ans 10 columns.and each points moves in a circular path?how to do this?i will be thankful to you if u find ou=ut a solution for me.
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