Converting time/dates to hours or number
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Hi I'm getting difficult to convert time dates to hours so i can set paying in my bill parking program . if i have 2 dates like this
t1 = datestr(datenum(now)); %answer is 13-Sep-2016 16:00:49
t2 = datestr(datenum(now)); %answer is 13-Sep-2016 20:00:14
i want to arithmetic (t2-t1) so i can get variable in hour or number . Please Help , Thanks b4 . I'm using matlab R2008a
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採用された回答
Walter Roberson
2016 年 9 月 13 日
Do not try to do date arithmetic on datestr . Do date arithmetic on the datenum values. The result will be in days. You can use datevec() or datestr() or plain arithmetic to convert the day difference to whatever form you prefer.
(Side note: now() returns a datenum directly.)
3 件のコメント
Walter Roberson
2016 年 9 月 13 日
t1 = datenum('13-Sep-2016 16:00:49');
t2 = datenum('13-Sep-2016 20:00:14');
time_diff = t2 - t1;
hours = floor(time_diff * 24);
minutes = round(time_diff - hours / 24);
fprintf('%d hours, %d minutes\n', hours, minutes);
その他の回答 (1 件)
Peter Perkins
2016 年 9 月 15 日
This doesn't help the OP (sorry obstac) who's using R2008a, but the same calculation using datetime:
>> t1 = datetime('13-Sep-2016 16:00:49')
t1 =
datetime
13-Sep-2016 16:00:49
>> t2 = datetime('13-Sep-2016 20:00:14')
t2 =
datetime
13-Sep-2016 20:00:14
>> time_diff = t2 - t1
time_diff =
duration
03:59:25
>> [h,m,s] = hms(time_diff)
h =
3
m =
59
s =
25
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