TAYLOR METHOD OF ORDER 3 ERROR

I want to solve the following equation using taylor's method of order 3. The equation is F=A(y-x). Initially y=-10.058 and x=0.368. A is constant with value equal to 35.

the code is:

M=183;
h = 0.001;

A = 35;
XX(1) = -10.058;
YY(1) = 0.368;

for i=1:((M^2)/3)
    F=A*(YY(i)-XX(i));
    H(i)=taylor(F,3,XX);
end;

It gives me following error--->

??? Undefined function or method 'taylor' for input arguments of type 'double'.

Error in ==> tay at 19 H(i)=taylor(F,3,XX);

ANY SUGGESTION OR SOLUTION..

Answer 1

[Walter Roberson]

taylor() is a routine from the symbolic toolkit, and it must be provided with a symbolic expression that includes at least one variable name. Instead you are trying to call taylor() with a purely numeric value: your F is a purely numeric formula.