how to convert wind direction to degrees?
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Hi all, I am working with wind speed and direction but the last is in form of compass, thus it required to convert it to degrees. could anyone kindly help me?
thank you in advance.
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Robert
2016 年 8 月 24 日
You could store the names and values in arrays and look up the angle corresponding to the matching name.
directionValues = 0:22.5:337.5
directionNames = {'N','NNE','NE','ENE','E','ESE','SE','SSE','S','SSW','SW','WSW','W','WNW','NW','NNW'};
directionValues(strcmp(directionNames,'NNW'))
Better yet, put that in an anonymous function
compass2degree = @(dirName) directionValues(strcmp(directionNames,dirName));
compass2degree('ESE')
その他の回答 (2 件)
Thorsten
2016 年 8 月 24 日
編集済み: Thorsten
2016 年 8 月 24 日
Set up a list of compass wind directions and corresponding angles in deg:
D = {'N'; 'E'; 'S'; 'W'}; Ddeg = [0; 90; 180; 270];
If you need more compass wind directions, just add them to D and Ddeg.
Create a table with compass wind directions as row names, and one column containing the corresponding angles in deg:
T = table(Ddeg);
T.Properties.RowNames = D;
T.Properties.VariableNames = {'deg'};
So you have
>> T
T =
deg
___
N 0
E 90
S 180
W 270
Now if you have a cell of different compass wind directions
myD = {'N' 'N' 'E' 'W' 'S'}
you can use this array as index into your table to get the corresponding angles in deg:
T(myD,:).deg
ans =
0
0
90
270
180
Robert Daly
2023 年 11 月 30 日
Updated answer using the dictionary data type added since R2022b. Intro to dictionaries blog
Dictionaries are vectorised so you can input a cell array of cardinal directions and it will return and array of corresponding wind angles in degrees.
Degrees = [0,0:22.5:337.5]'
Direction = {'','N','NNE','NE','ENE','E','ESE','SE','SSE','S','SSW','SW','WSW','W','WNW','NW','NNW'}';
Cardinal = dictionary(Direction,Degrees)
WindDir = {'NNE','N','SSE','S','SSW','NE','ENE'}
WindDeg = Cardinal(Wind)
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