Is the equality min(a/(b+1), c/(d+1))=m​in(a,c)/(m​in(b,d)+1) hold?

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kader
kader 2016 年 8 月 3 日
コメント済み: Guillaume 2016 年 8 月 3 日
Dear Altruist,
With the Matlab simulation i.e numerically I can prove that the following equality holds.
min(a/(b+1), c/(d+1))=min(a,c)/(min(b,d)+1), where a, b, c, d are the variables.
Can anyone please prove that the above equality holds through the mathematical derivation?
Thanks in advance Kader

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Thorsten
Thorsten 2016 年 8 月 3 日
It does not hold. Try
a = 1; b = 8; c = 4; d = 3;
min(a/(b+1), c/(d+1))
min(a,c)/(min(b,d)+1),
  3 件のコメント
kader
kader 2016 年 8 月 3 日
So, is there any possible condition can be provided for which it holds?
Guillaume
Guillaume 2016 年 8 月 3 日
Possibly. However, this has nothing to do with matlab, so would need to be asked on a math forum.

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