image flipping without built in commands
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Hey everyone, I am trying to horizontally flip an image using arrays only. What I tried to do with this code was to go through every row in the original image and assign the values of every pixel in a row of the original image to a pixel in the processed image with the same row but reversed order. (meaning the value of the pixel in the first row the first column of the original image would be assigned to the pixel in the first row the last column of the processed image)
original_img=imread('someimg.jpg');
[row,col,layers] = size(original_img);
processed_img = zeros(row,col,layers);
processed_img(1:row,col:-1:1,:) = original_img(1:row,1:col,:);
The problem is that the algorithm seems to work for some pixels in the image but most of the processed image is still white (since it was initially an array of zeros). I couldn't get my head around the reason why this algorithm does not work. I know there are built-in functions to flip images but I am trying to do it by using array properties. Thanks a lot for your help.
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その他の回答 (2 件)
James Tursa
2016 年 7 月 22 日
Did you mean this?
newcat(1:row,1:col,:) = cat(row:-1:1,1:col,:);
Or this?
newcat(1:row,1:col,:) = cat(1:row,col:-1:1,:);
3 件のコメント
Johann Sebastian Bach
2016 年 7 月 22 日
James Tursa
2016 年 7 月 22 日
Can you elaborate on "doesn't work?" What result are you expecting?
Johann Sebastian Bach
2016 年 7 月 23 日
Image Analyst
2016 年 7 月 23 日
0 投票
You should never use variables that are also built in functions. And you not only did it once, but twice. Don't use cat and dim as variables because those are built in functions.
What do you mean by "flip"? Flip vertically or horizontally or both? And why can't you use built-in functions? Are you asking us to do your homework for you?
1 件のコメント
Johann Sebastian Bach
2016 年 7 月 23 日
編集済み: Johann Sebastian Bach
2016 年 7 月 23 日
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