Why does my output formatting not print multiple times?

This is the best I can get from this MATLAB 2016 Student source code:

fmt_num10='%10.4f%10.4f%10.4f%10.4f%10.4f%10.4f%10.4f%10.4f%10.4f%10.4f\n';
fmt_str80='%s\n'
  for ken=1,KENG;
      fprintf(fidout,'TITJ\n')
      fprintf(fidout,fmt_str80,TITJ(k,:))
      fprintf(fidout,'D6,D7,D8,D10,D11,D12,D13,D14,D15,D16\n')
      fprintf(fidout,fmt_num10,[D6(k),D8(k),D10(k),D11(k),D12(k),D13(k), ...
          D14(k),D15(k),D16(k)])
  end

I'm expecting the following KENG times, but it only prints the last request:

TITJ
*---MAIN GEAR DWT---*
D6,D7,D8,D10,D11,D12,D13,D14,D15,D16
  -97.7830    0.0000  221.2340   10.4380    0.9146    0.0000    0.0000    0.0000    0.4043

[Kenneth Lamury]

Sorry about that, added D7(k) to the mix. It still only prints the first listing, not others. Any other suggestions?

[Kenneth Lamury]

Again, sorry about that. Changing ken=1,KENG to k=1:KENG, and adding D7(k) to output string fixed my problems.

Answer 1

[Star Strider]

One possibility is that your for loop increments ‘ken’ but the only vector reference I can see references ‘k’. I suspect you define ‘k’ somewhere else (perhaps in another loop) in your code earlier, and its value remains the maximum value it reaches in that loop, so the subscript reference would be to that unchanging value.

[Kenneth Lamury]

Sorry about that. Changed ken to k. But now it only prints the first reading and not all of them. Any further comments?

[Star Strider]

It should go through the entire loop and print everything at each iteration.

I don’t have your data, but when I do a similar loop:

mtx = randi(9, 5, 6);
fmt = ['\t' repmat('%3.0f', 1, size(mtx,2)) '\n'];
for k1 = 1:size(mtx,1)
    fprintf(1, 'Row %.0f:\n',k1)
    fprintf(1, fmt, mtx(k1,:))
end

it prints out correctly.

I just noticed that you left out ‘D(7)’ here:

fprintf(fidout,fmt_num10,[D6(k),D8(k),D10(k), ...

Not critical, but you may want to include it.

You can also use the repmat function here:

fmt_num10 = [repmat('%10.4f', 1, 10) '\n'];

Answer 2

[Walter Roberson]

for k=1:KENG

not

for k=1,KENG

[Kenneth Lamury]

Sorry about that. I need to remember to switch my thinking caps. Still applying FORTRAN & MathCad logic to MATLAB.