A question about different image size generation using Matlab
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Hello everyone!
I need your help! Can anyone please tell me why, the Y1 becomes empty and its size changes when I input a true color image ?
X1 = double(imread('true_color_image'));
Y1 = padarray(X1(end-1:end,end-1:end),[1 1],'replicate','pre')
size(X1)
size(Y1)
Y1 =
0 0 0
0 0 0
0 0 0
ans =
120 120 3
ans =
3 3
While when I use input data, as shown below, Y1 does not change:
X2 = [1 2 3; 4 5 6; 7 8 9]
Y2 = padarray(X2(end-1:end,end-1:end),[1 1],'replicate','pre')
size(X2)
size(Y2)
X2=
1 2 3
4 5 6
7 8 9
Y2=
5 5 6
5 5 6
8 8 9
ans =
3 3
ans =
3 3
What can I do so that the size of Y1 does not change (i.e. remains same as X1) ?
Thank you!
5 件のコメント
採用された回答
Guillaume
2016 年 7 月 5 日
X1(end-1:end,end-1:end)
Since you're using 2D indexing to index a 3D matrix, this only return values from the 1st plane (the red colour plane). This is equivalent to
X1(end-1:end,end-1:end, 1)
If you want a 3D matrix as output, you must pass a 3D matrix as input, so:
Y1 = padarray(X1(end-1:end,end-1:end, :), [1 1], 'replicate', 'pre')
Note that the above will work on greyscale images as wel, since the : will match the only colour plane.
3 件のコメント
Guillaume
2016 年 7 月 5 日
Well, end-1:end only select the last 2 columns/rows. So padding it by 1 is always going to give you 3 columns/rows.
Matlab is doing exactly what you're asking. What you're asking is obviously not what you really mean. You haven't say what it is though.
If you want to pad the whole array:
Y1 = padarray(X1, [1 1], 'replicate', 'pre');
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