Efficient moving average of scattered data

9 ビュー (過去 30 日間)
Chad Greene
Chad Greene 2016 年 6 月 28 日
回答済み: Chris Turnes 2017 年 3 月 9 日
I have some scattered data and I'd like to take something similar to a moving average, where I average all values with in some radius of each point. I can do this with a loop, but I'd like a more efficient approach. Any ideas?
Here's a working example I'd like to make more efficient:
x = randi(100,45,1) + 20+3*randn(45,1) ;
y = 15*sind(x) + randn(size(x)) + 3;
figure
plot(x,y,'bo')
radius = 10;
ymean = NaN(size(x));
for k = 1:length(x)
% Indicies of all points within specified radius:
ind = abs(x-x(k))<radius;
% Mean of y values within radius:
ymean(k) = mean(y(ind));
end
hold on
plot(x,ymean,'ks')
legend('scattered data','radial average','location','southeast')
  1 件のコメント
Walter Roberson
Walter Roberson 2016 年 6 月 28 日
When I read the title I thought you might mean "sparse", and was thinking about how I might do an efficient moving average on sparse data.

サインインしてコメントする。

採用された回答

Chad Greene
Chad Greene 2016 年 6 月 30 日
I turned this into a generalized function called scatstat1, which is on the file exchange here.
  1 件のコメント
Chad Greene
Chad Greene 2016 年 6 月 30 日
And a 2D version called scatstat2.

サインインしてコメントする。

その他の回答 (2 件)

Chris Turnes
Chris Turnes 2017 年 3 月 9 日
If you can upgrade to R2017a, this functionality can now be achieved through the 'SamplePoints' name-value pair in the moving statistics. For your example, you would do something like movmean(y, 2*radius, 'SamplePoints', x); (though you'd need to sort your x values first).

Walter Roberson
Walter Roberson 2016 年 6 月 28 日
pdist() to get all of the distances simultaneously. Compare to the radius. Store the resulting mask. Multiply the mask by repmat() of the y value, and sum along a dimension. sum the mask along the same dimension and divide the value sum by that count. Result should be the moving average.
  3 件のコメント
Walter Roberson
Walter Roberson 2016 年 6 月 30 日
編集済み: Walter Roberson 2016 年 6 月 30 日
I wonder if looping pdist2() would be efficient? Eh, it probably just adds unnecessary overhead to a simple Euclidean calculation.
Chad Greene
Chad Greene 2016 年 7 月 1 日
Also adds a Stats Toolbox dependency. I'll have to keep pdist in mind for future applications though. Thanks for the suggestion!

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeCreating and Concatenating Matrices についてさらに検索

製品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by