Datetime from Unix time miliseconds
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Hello,
I am using a data source that gives a unix time(down to miliseconds), I want to convert this to a date string, I am currently using
dt = datestr(datetime(values(1)/1000, 'ConvertFrom', 'posixtime') + hours(2)); %add 2 hours for gmt +2
The division by 1000 is because the datestring can't handle mili second unix time.
With google I can't find a way to tell matlab to include milliseconds to datetime, but I really need the milliseconds. Did I overlook something?
Thanks in advance,
Bearpie
P.S. Matlab 2016A
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その他の回答 (2 件)
Peter Perkins
2016 年 8 月 3 日
It's not entirely clear to me what you're starting out with. "unix time" isiusually measure in seconds since 1970, you may have seconds with a fraction, or you may have seconds*1000 as an integer. I'm thinking the latter based on your code. You're also correcting for local time zone in your string.
>> unixmillis = 1470243132021
unixmillis =
1470243132021
>> t = datetime(unixmillis/1000,'ConvertFrom','posixTime','TimeZone','America/New_York','Format','dd-MMM-yyyy HH:mm:ss.SSS')
t =
03-Aug-2016 12:52:12.021
>> char(t)
ans =
03-Aug-2016 12:52:12.021
Numerically, the division by 1000 isn't the greatest, but for many purposes (including, making a string), it's good enough. You could also do this:
>> datetime(1970,1,1,'Format','dd-MMM-yyyy HH:mm:ss.SSS') + milliseconds(unixmillis)
ans =
03-Aug-2016 16:52:12.021
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Guillaume
2016 年 6 月 17 日
Both datetime and datestr support milliseconds just fine. You just need to tell them you want the milliseconds displayed.
To force datestr to show milliseconds:
dt = datestr(yourdatetime, 'dd-mmm-yyyy HH:MM:SS:FFF'); %FFF is for millisecond
Once you've converted to datestring you've lost all the information not encoded in the string, so instead I would keep the information as datetime, and convert the datetime to a string as required
yourdatetime.Format = 'dd-MMM-yyyy HH:mm:ss SSS'); %note that datetime format syntax is not the same as datestr
c = char(yourdatetime) %to get a string out of a datetime
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