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How to convert char to number?

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Sandy
Sandy 2016 年 6 月 10 日
コメント済み: Azzi Abdelmalek 2016 年 6 月 10 日
I have a data set that I am trying to format as follows:
month = data (:, 2); % (2276x1)
month =sprintf('%02d\n',month)
The problem is this gives me:
Name Size Bytes Class
month 1x6828 13656 char
I need it to be a single column of NUMBER data (2276x1) in the format I specified. I tried using str2num but this makes my data lose the formatting I want.
Please help and thank you!
  5 件のコメント
Azzi Abdelmalek
Azzi Abdelmalek 2016 年 6 月 10 日
When you write:
a=05
This number will be displayed as 5. The only way to display it with padded 0 is to use a string.
sprintf('%02d',5)
Image Analyst
Image Analyst 2016 年 6 月 10 日
Don't use month as a variable name because it's a built-in function. What does data represent, and especially column 2 of data? Why is month 2276 characters long? The month names I know of are less than 10 characters, like September.

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Azzi Abdelmalek
Azzi Abdelmalek 2016 年 6 月 10 日
編集済み: Azzi Abdelmalek 2016 年 6 月 10 日
B=sprintf('%02d\n',A)
sprintf is used to display your data A in a format of your choice, your data are converted to string B. Your data are still in your original array A. Why do you want to convert B ?
For example, if you have a number 5, if you want to display it as 05 you need to convert it to a string '05'.
  4 件のコメント
Sandy
Sandy 2016 年 6 月 10 日
Is there a way to save what is shown in the display? For example, if my numbers are 5, 6, 7, I'd like to export a text file with 05, 06, 07.
Azzi Abdelmalek
Azzi Abdelmalek 2016 年 6 月 10 日
If you want to save your data as double, just save your original array. nobody will see it!

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