Reducing time code takes to run using profile viewer

This code below takes up about 40 seconds when the size of the matrix is (13,5,2000) All im doing is removing any matrixs which are repeated.
ie if big_data(:,:,x)==big_data(:,:,x+1) then remove one of the matrixs. I know there is a unique function, but I cant seem to get it to work how I want. When I scale it up to matrixs of size (13,5,10000), its just taking too long.
Is there a better way? thanks.
while x<length(big_data(1,1,:))+1
while y<length(big_data(1,1,:))
y=y+1;
if big_data(:,:,x)==big_data(:,:,y)
big_data(:,:,y)=[];
y=y-1;
end
end
x=x+1;
y=x;
end

回答 (2 件)

Jan
Jan 2012 年 2 月 12 日

0 投票

Shrinking a large array iteratively requires a lot of resouerces, equivalently to growing. Better use a logical vector to mark subarrays and delete them all together after the loops.
Paul
Paul 2012 年 2 月 14 日

0 投票

Are you saying to do something like, replace
big_data(:,:,y)=[];
with
to_delete(count)=y
then once the loop is finished
big_data(:,:,to_delete)=[]

1 件のコメント

Sean de Wolski
Sean de Wolski 2012 年 2 月 14 日
yup.
But be sure to preallocate to_delete.
Or even better use a logical vector:
to_delete = false(1,1,size(big_data,3));
while ...
to_delete(1,1,index) = true
end
etc

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