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Martix are updating without entering into "for" loop,

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kintali narendra
kintali narendra 2016 年 6 月 2 日
コメント済み: kintali narendra 2016 年 6 月 2 日
I Want to eWithDeltaL, eWithDeltaK to be updated during the time intervals mentioned.
function [out] = motor(In)
e = In(1);
%there is some other code
Clock = In(4);
clock = int64(Clock);
for clock = 0:0.999
eWithNoChange = [];
eWithNoChange(end+1) = e;
end
for clock = 1.0000:1.999
deltaL = L*0.1;
eWithDeltaL = [];
eWithDeltaL(end+1) = e;
end
Out = [deltaL,deltaK,clock]

採用された回答

Walter Roberson
Walter Roberson 2016 年 6 月 2 日
It is being updated: it is having the previous value(s) removed from it and the new value is being stored in it, every iteration of the loop.
What you probably want is to initialize the array once before the loop instead of initializing it in every iteration of the loop. For example,
eWithNoChange = [];
for clock = 0:0.999
eWithNoChange(end+1) = e;
end
Side note:
When you have a for loop, after the loop is finished executing, the index variable (such as clock) is left as the last value that was assigned to it. For example,
for I = 1 : 10
disp(I);
end
then since 10 was the last value assigned to I, after the loop, I will be left as the value 10 .
  1 件のコメント
kintali narendra
kintali narendra 2016 年 6 月 2 日
I made the changes you mentioned ,but new column is added to matrix without considering the "for" loop.
function [Out] = LMAImplementation_Motor(In)
persistent eWithNoChange eWithDeltaL
Clock = In(4);
clock = int64(Clock);
for clock = 0:0.999
deltaK = 0; deltaL = 0;
eWithNoChange(end+1) = e;
end
for clock = 1.0000:1.999
deltaL = L*0.1;
eWithDeltaL(end+1) = e;
end
Out = [deltaL,deltaK,Clock];

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