how to Design PID controller for second order untable process
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How a PID controller can be designed for a second order SISO process, of the form -a/S^2-b, where a,b>0 .
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Arkadiy Turevskiy
2012 年 2 月 13 日
Not sure if that is what you are looking for, but here is how you could do it in Control System Toolbox:
>>a=1; % change to desired value
>>b=4; % change to desired value
>>s=tf('s');
>>plant=-a/(s^2-b);
>>C=pidtune(plant,'PID'); design pid controller
>>step(feedback(C*plant,1)); plot the step response of the closed-loop system
>>pidtool(plant); % open the GUI for interactive tuning
HTH. Arkadiy
2 件のコメント
Walter Roberson
2012 年 2 月 19 日
pidtune is new as of R2010b
http://www.mathworks.com/help/toolbox/control/rn/bsllzup-1.html
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