adding index to matrix rows

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Ali
Ali 2016 年 5 月 27 日
コメント済み: Allison Chua 2020 年 10 月 6 日
I have a matrix like this
1 0
0 2
2 1
0 3
3 2
2 0
4 1
1 6
6 4
6 1
I would like to have the following matrix, please help me if you have the answer.
0: 1 0
1: 0 2
2: 2 1
3: 0 3
4: 3 2
5: 2 0
6: 4 1
7: 1 6
8: 6 4
9: 6 1

採用された回答

Guillaume
Guillaume 2016 年 5 月 27 日
編集済み: Stephen 2016 年 5 月 27 日
Please use the code format button {}Code rather than putting spaces between each line.
A matrix can only contain numbers, colons are not allowed. If it's only for display that you want that, there's no simple way to force matlab to display matrices like this.
Possibly, you can convert the matrix into a table and assign names to the rows:
m = [1 0;0 2; 2 1; 0 3; 3 2; 2 0; 4 1];
t = array2table(m, 'RowNames', sprintfc('%d:', 1:size(m, 1)), 'VariableNames', sprintfc('col%d', 1:size(m, 2)))
Otherwise, you'll have to write your own display function which is far from trivial if you want it to play nicely with format.
  6 件のコメント
Ali
Ali 2016 年 5 月 27 日
Many thanks Guillaume. you helped me a lot

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その他の回答 (1 件)

Renato Agurto
Renato Agurto 2016 年 5 月 27 日
編集済み: Renato Agurto 2016 年 5 月 27 日
Is this what you want? Or what do you mean with ':' in a matrix?
A = [1 0;
0 2;
2 1;
0 3;
3 2;
2 0;
4 1;
1 6;
6 4;
6 1];
B = [(0:size(A,1)-1)' A];
  2 件のコメント
Allison Chua
Allison Chua 2020 年 10 月 6 日
@Renato Agurto - thank you SO much!!! I'm so terrible at Matlab syntax, and this was exactly what I needed.

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