draw min squares in black and white

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Ahmed raafat
Ahmed raafat 2016 年 5 月 27 日
編集済み: Roger Stafford 2016 年 5 月 28 日
Hi every
I want to plot min squares in black and white like the attachment
I had an idea (I didn't try it that i make the 3-dim image matrices)
Is there other solutions???
  3 件のコメント
Ahmed raafat
Ahmed raafat 2016 年 5 月 27 日
I mean with like a grid with square size 1cm*1cm
And it is a task
Ahmed raafat
Ahmed raafat 2016 年 5 月 27 日
Please see the attachment to understand me of min squares

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採用された回答

Roger Stafford
Roger Stafford 2016 年 5 月 27 日
Do the following:
m = 16; n = 33;
A = false(m,n);
A(1,17) = true;
for k = 2:m
v = 2:n-1;
A(k,v) = A(k-1,v-1)~=(A(k-1,v)|A(k-1,v+1));
end
Then use the A(:,2:n-1) matrix to determine which squares are to be black (true) and which are white (false.) I’ll leave the plotting up to you.
  2 件のコメント
Ahmed raafat
Ahmed raafat 2016 年 5 月 28 日
Thanks mr.Roger
It worked
Roger Stafford
Roger Stafford 2016 年 5 月 28 日
編集済み: Roger Stafford 2016 年 5 月 28 日
It should be noted here that your “rule 30” presumably refers to a logic method devised by Stephen Wolfram for generating a pseudo-random sequence of binary digits. The “30” refers to the binary representation of the truth table involved: 00011110.

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その他の回答 (1 件)

Image Analyst
Image Analyst 2016 年 5 月 28 日
Seems like homework, so here's a hint. Look at the pattern. The three binary squares above are 7, 6, 5, 4, 3, 2, 1, 0. You just need to turn the three elements above the current element into a decimal number like
decNumber = 4*A(row-1, col-1) + 2*A(row-1, col) + A(row-1, col+1);
Then if decNumber is 1 through 4 inclusive, then set the value to 1, otherwise it's zero.

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