Global variable scope is not applied in try and catch

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Ankit Singh
Ankit Singh 2016 年 5 月 7 日
コメント済み: Image Analyst 2016 年 5 月 7 日
global Name;
clear all;
close all force;
prompt = 'Enter Name';
%Name = input(prompt,'s');
Name = input(prompt);
for i=1:10
Depth;
DetectFaceandEyes;
calcEyedistance
try
load db;
euclideanDistance = round(euclideanDistance,1);
F=[euclideanDistance Name distanceAsString];
db=[db;F];
save db.mat db
catch
db =[euclideanDistance Name distanceAsString];
save db.mat db
end
end
Undefined function or variable 'Name'.
Error in Trianing (line 18) db =[euclideanDistance Name distanceAsString];

採用された回答

Azzi Abdelmalek
Azzi Abdelmalek 2016 年 5 月 7 日
編集済み: Azzi Abdelmalek 2016 年 5 月 7 日
global Name;
clear all;
close all force;
prompt = 'Enter Name';
Name = input(prompt)
You declare Name as global, then you clear all the variables, finally you ask to enter the variable Name. You have to remove the: clear all
  6 件のコメント
Ankit Singh
Ankit Singh 2016 年 5 月 7 日
編集済み: Ankit Singh 2016 年 5 月 7 日
yes it solved
Image Analyst
Image Analyst 2016 年 5 月 7 日
If it wasn't removing the clear, then what was the solution?

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その他の回答 (1 件)

Image Analyst
Image Analyst 2016 年 5 月 7 日
編集済み: Image Analyst 2016 年 5 月 7 日
You have
global Name;
clear all;
Now, the help says "A variable that is global, then clear removes it from the current workspace, but it remains in the global workspace". Now I think that's a little ambiguous - is Name there or not? When you recreate Name with a call to input():
Name = input(prompt);
Is that a new local variable called Name, or is that the same Name in the global workspace again? I'm not sure. My guess is that it's a local variable that unfortunately now has the same name as the variable in the global workspace. But they're two different variables now. The best thing to do is (like Azzi said) to remove the call to clear.

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