code generation for FFT is void
1 回表示 (過去 30 日間)
古いコメントを表示
I want to generate code from my m-code which computes an FFT. When I see the results the c-function is void when the result should be a complex double?
0 件のコメント
回答 (1 件)
Walter Roberson
2016 年 5 月 5 日
The generated code has pointers passed in to it. C cannot handle multiple outputs, so Mathworks generates code that passes in pointers for all outputs, rather than special-casing the first output.
参考
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!