how can i calculate the rms of a vector ?

7 ビュー (過去 30 日間)
Mallouli Marwa
Mallouli Marwa 2016 年 5 月 3 日
コメント済み: Camille Dingam 2020 年 3 月 10 日
my problem consist to calculate the rms of v using for loop. But this for loop display vrms as zeros
for i=1:2500
vs=sum((v(i,1))^2)
end
vrms=sqrt((1/2501)*vs);

採用された回答

Guillaume
Guillaume 2016 年 5 月 3 日
You get 0 because the last value in v is 0 and your vs is just the last value of v squared. Notice that sum(v(i)) is just v(i). You probably meant:
vs = vs + v(i)^2;
Your loop is badly constructed by the way. For a start you shouldn't hardcode the length of the vector, you can get it with numel. You also shouldn't use subscript indexing when linear indexing suffices. That way, it would work with row or column vectors:
vs = 0;
for i = 1:numel(v)
vs = vs + v(i)^2;
end
vrms = sqrt(vs / (numel(v)+1));
In any case, the loop is completely unnecessary:
vs = sum(v.^2);
vrms = sqrt(vs / (numel(v)+1));
  2 件のコメント
Mallouli Marwa
Mallouli Marwa 2016 年 5 月 3 日
thank's a lot
Tahariet Sharon
Tahariet Sharon 2017 年 11 月 25 日
編集済み: Tahariet Sharon 2017 年 11 月 25 日
why do you divide by plus 1?

サインインしてコメントする。

その他の回答 (1 件)

Star Strider
Star Strider 2016 年 5 月 3 日
The root-mean-square calculation is a one-line calculation:
v = sin([1:0.1:20]*2*pi); % Create Data
rms = sqrt(mean(v.^2));
  3 件のコメント
Star Strider
Star Strider 2016 年 5 月 4 日
My pleasure.
Camille Dingam
Camille Dingam 2020 年 3 月 10 日
I have done the work with normal people and dysarthria(sick person) audio datasets. I have extracted the rms(root mean squared) energies of their vowels, and i found that dysarthria rms energies of the vowels are mostly high than normal person, please i try to make a conclusion of it. If anyone have some ideas of rms energy, can you tell me why the vowels rms energies are high in dysarthria? Thank you for your reply

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeLoops and Conditional Statements についてさらに検索

タグ

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by