How to do this coding for this equation?

i=25/50001*sin100t+2/100*cos100t+Ce^-2t, 
t=0

Answer 1

[Walter Roberson]

syms C t
eqn = i == 25/50001*sin(100*t)+2/100*cos(100*t)+C*exp(-2*t); 
eqn0 = subs(eqn,t,0);
solve(eqn0, C)

[Fairuz Ridwan]

Thanks for the help.. But, exactly I have to plot the equation. Haha, I'm not sure how.. Will you help.

[Walter Roberson]

There is not much to plot. After the substitution of t being 0, you have one equation in one unknown (C), and that has a single solution. Your plot would be at most a single point on the complex plane.

Note: In MATLAB, i represents sqrt(-1)

[Fairuz Ridwan]

Sorry sir, I have try to plot it but I don't get.. DO you know why?

[Walter Roberson]

syms C t
t0 = 0;
eqn = i == 25/50001*sin(100*t)+2/100*cos(100*t)+C*exp(-2*t); 
eqn0 = subs(eqn,t,t0);
sol = solve(eqn0, C);
plot(real(sol), imag(sol), 'r*')
xlabel('real plane')
ylabel('imaginary plane');

The single red dot that results is the plot. The entire solution to the equation is:

C = - 1/50 + 1i

[Fairuz Ridwan]

Sorry sir, the real task is I need to plot the equation (i=25/50001*sin100t+2/100*cos100t+Ce^-2t, t=0 ). This equation is the solution for a question. Then, I have to plot it by using matlab, I have try few code but the graph that I got just blank without plot. I'm not sure why because I'm still learning. Thanks for your help sir. If you have any idea?

[Walter Roberson]

The above code is the solution for that.

Remember, i is the imaginary unit, http://www.mathworks.com/help/matlab/ref/i.html, the square root of negative 1. You have defined a value for the left side of the equation, sqrt(-1), and you have defined a t value, 0. Your equation comes evaluates down to sqrt(-1) = 1/50 + C . There is a single C that solves that equation, C = -1/50 + sqrt(-1) . That leads to a single point on the plot.

[Fairuz Ridwan]

Oh, I see that's mean C just the constant. Thanks for your help sir. Really appreciate.

Answer 2

[louis rassinfosse]

Try to use the symbolic toolbox;

syms t

I=.....

t=...

And you should get an answer

[Fairuz Ridwan]

I'm blank with the command exactly.. Haha.. btw thanks a lot.