if i have some matrix how can i do this operation on it ?

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Firas Al-Kharabsheh
Firas Al-Kharabsheh 2016 年 4 月 29 日
コメント済み: Walter Roberson 2016 年 4 月 29 日
if i have matrix where the size of it is (2,5) and i have a matrix
a = [ 1 3
3 1 ]
* where a matrix show how many of ones will be in the f matrix and between these group of ones just one zero
how to generate matrix like this
f = [ 1 0 1 1 1
1 1 1 0 1 ]

採用された回答

Azzi Abdelmalek
Azzi Abdelmalek 2016 年 4 月 29 日
This is not the best way, but it works
a = [ 1 3
3 1 ]
b=arrayfun(@(x) [0 ones(1,x)],a,'un',0)
c=arrayfun(@(x) cell2mat(b(x,:)),(1:size(a,1))','un',0)
d=cell2mat(c);
out=d(:,2:end)
  2 件のコメント
Firas Al-Kharabsheh
Firas Al-Kharabsheh 2016 年 4 月 29 日
if i have this code to search about the row which make the if statement is true and put it in F matrix
a = [3 2 0
2 1 1
2 1 1
2 1 0
3 2 0
4 3 0
5 4 0
4 3 0
4 3 0
10 0 0 ]
a1=sum(a,2)
b1=sum(a~=0,2)
n1 = 10
m1 = 10
[n,m]=size(a)
F = zeros(n1,m1)
for k=1:n
if 10 == (a1(k) + (b1(k) -1 ))
b=arrayfun(@(x) [0 ones(1,x)],a,'un',0)
c=arrayfun(@(x) cell2mat(b(x,:)),(1:size(a,1))','un',0)
d=cell2mat(c);
out=d(:,2:end)
end
end
the final answer will be
F = [ 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0
1 1 1 1 1 0 1 1 1 1
0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0
1 1 1 1 1 1 1 1 1 1 ]
Walter Roberson
Walter Roberson 2016 年 4 月 29 日
You duplicate your questions too much, which is a pain to clean up after. The volunteers can either spend time answering code or they can spend time cleaning up questions, but they don't have time to do both.

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