How can i speed up the following?
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Can anyone help me speed up what is written below? I have a large code and this routine, while seemingly fast, gets called a great deal.
a = rand(31,31);
TmTn = rand(301,301,31,31);
f = zeros(size(TmTn,1),size(TmTn,2));
[qe pe] = size(a);
for p = 1:pe
for q = 1:qe;
f = f + a(q,p).*TmTn(:,:,p,q);
end
end
Note: I have tried various sequences of permute, repmat, direct multiplication, moving the sum, parfor and reshape.
Thanks in advance, Bill
2 件のコメント
Adam
2016 年 4 月 28 日
Have you run the profile on your full "large code" to determine how much of the total time is actually spent on this routine?
採用された回答
Roger Stafford
2016 年 4 月 29 日
You can turn this into ordinary matrix multiplication. Since matlab is specially optimized for matrix multiplication, it might be faster.
a = rand(31,31);
TmTn = rand(301,301,31,31);
a2 = reshape(a.',[],1); % Transpose 'a' and make it a column vector
TmTn2 = reshape(TmTn,[],31^2); % Change TmTn to a 2D matrix
f = reshape(TmTn2*a2,301,301); % Use ordinary matrix multiplication and then reshape back
その他の回答 (2 件)
Arnab Sen
2016 年 4 月 28 日
Hi Bill, You can try to replace the loop by vectorization. Something like below:
a = rand(31,31); TmTn = rand(301,301,31,31);
f = zeros(size(TmTn,1),size(TmTn,2));
[qe pe] = size(a);
TmTn2=reshape(TmTn,301*31,301*31);
TmTn1=mat2cell(TmTn2,size(TmTn,1)*ones(1,p),size(TmTn,2)*ones(1,q));
b=a';
C= cellfun(@(x,y) x.*y, mat2cell(b,ones(1,pe),ones(1,qe)),TmTn1, 'UniformOutput',false);
f=sum(cat(3,C{:,:}),3);
Using 'perfor' is another option where we can multiple for loops in parallel. For more detail refer to the following link:
2 件のコメント
Adam
2016 年 4 月 28 日
編集済み: Adam
2016 年 4 月 28 日
Be careful using cellfun if speed is your aim, it is almost always slower than a for loop, but in either case the profiler or a timeit wrapped around the two options should help to check that.
Working with cell arrays in general is a lot less performant than numeric arrays if you are able to use numeric arrays instead.
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