How can i make the sum of matrix elements>0 under the condition that there are min 3 zeros between the sums?
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I hava a matrix: a=[2 3 0 0 4; 0 0 0 0 0; 0 5 3 0 4; 14 4 0 1 1; 0 0 0 0 0; 0 0 0 7 9; 0 0 0 0 0; 0 0 0 0 0; 9 6 0 0 1; 1 1 1 0 0];
How can i make the sum of elements>3, under the condition that there are at least 3 zeros between the last element of one and the first element of the next sum?
Output should be: E=[9 32 16 19]
thanks!
2 件のコメント
Image Analyst
2016 年 4 月 23 日
Next sum? Why is there more than one sum??? Looks like you need to read this before you fix your post.
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Azzi Abdelmalek
2016 年 4 月 23 日
編集済み: Azzi Abdelmalek
2016 年 4 月 23 日
a=[2 3 0 0 4; 0 0 0 0 0; 0 5 3 0 4; 14 4 0 1 1; 0 0 0 0 0; 0 0 0 7 9; 0 0 0 0 0; 0 0 0 0 0; 9 6 0 0 1; 1 1 1 0 0]
b=reshape(a',1,[]);
id=~b;
ii=strfind(id,[1 1 1 0])+2;
ii=[0 ii numel(b)];
for k=1:numel(ii)-1
out(k)=sum(b(ii(k)+1:ii(k+1)));
end
out
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