Time Varying Input in Matrix

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Ian Smith
Ian Smith 2016 年 4 月 22 日
編集済み: Ian Smith 2016 年 4 月 23 日
I have a time varying input, K.
A= [0; 0; K];
B= [5 -3 2; 2 -3 1; 3 2 1];
for x=1:length(t)
A= [0; 0; K];
B= [5 -3 2; 2 -3 1; 3 2 1];
C = linsolve(B, A);
end
I am getting the error that the answer changes size every loop iteration how can I solve this. Thanks

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Star Strider
Star Strider 2016 年 4 月 22 日
‘I am getting the error that Icell(x) changes size every loop iteration how can i solve this.’
That’s just a warning, not an error.
The way to prevent it is to ‘preallocate’ ‘Icell’ before the loop. One way to do this is:
Icell = nan(1, length(t));
This will create a row vector of NaN values that your ‘Icell’ assignment just has to fill, rather than creating a new value for it with each iteration. (Other options in addition to nan are zeros and inf. All will create the vector you want, the only difference being the values it fills them with.)
  2 件のコメント
Ian Smith
Ian Smith 2016 年 4 月 22 日
perfect thank you very much
Star Strider
Star Strider 2016 年 4 月 22 日
My pleasure.

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