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Fausto Arinos Barbuto 2016 年 4 月 19 日
コメント済み: Walter Roberson 2016 年 4 月 20 日
The following lines:
>> syms s;
>> Fs = s^2;
>> ilaplace(Fs)
produce this output:
ans =
dirac(t, 2)
suggesting (to me) that there is a dirac() function that takes two arguments. However, for example,
>> dirac(1,2)
outputs an error ("Too many input arguments."). Can someone give me an explanation to that?
Thanks.

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回答 (1 件)

Wayne King 2016 年 4 月 19 日

I think you mean
dirac(2,t)
and not dirac(t,2)
There is a function in Symbolic Toolbox called dirac() that takes the following syntax
dirac(n,x)
where n is the order of the derivative. Of course derivative is understood here in the sense of distributions.
So dirac(2,t) is the 2nd derivative of the Dirac distribution with respect to the variable t.
See the reference page:
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Walter Roberson 2016 年 4 月 20 日
Hmmm, try
dirac(sym('2'), sym('1'))
if that does not work then try
evalin(symengine, 'dirac', 2, 1)

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