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Question about ilaplace()

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Fausto Arinos Barbuto
Fausto Arinos Barbuto 2016 年 4 月 19 日
コメント済み: Walter Roberson 2016 年 4 月 20 日
The following lines:
>> syms s;
>> Fs = s^2;
>> ilaplace(Fs)
produce this output:
ans =
dirac(t, 2)
suggesting (to me) that there is a dirac() function that takes two arguments. However, for example,
>> dirac(1,2)
outputs an error ("Too many input arguments."). Can someone give me an explanation to that?

回答 (1 件)

Wayne King
Wayne King 2016 年 4 月 19 日
編集済み: Wayne King 2016 年 4 月 19 日
I think you mean
and not dirac(t,2)
There is a function in Symbolic Toolbox called dirac() that takes the following syntax
where n is the order of the derivative. Of course derivative is understood here in the sense of distributions.
So dirac(2,t) is the 2nd derivative of the Dirac distribution with respect to the variable t.
See the reference page:
  4 件のコメント
Walter Roberson
Walter Roberson 2016 年 4 月 20 日
Hmmm, try
dirac(sym('2'), sym('1'))
if that does not work then try
evalin(symengine, 'dirac', 2, 1)


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