How to sort a matrix using loops?

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Michael Porter
Michael Porter 2016 年 4 月 16 日
編集済み: John BG 2016 年 4 月 24 日
I need to sort a matrix from least to greatest without the sort function. It needs to be done in nested loops. For example, I need to take the matrix [9 5;7 4;8 6] and sort it into [4 5;6 7;8 9].
  1 件のコメント
Roger Stafford
Roger Stafford 2016 年 4 月 17 日
See this site for a variety of possible algorithms you might use:
https://en.wikipedia.org/wiki/Sorting_algorithm

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回答 (1 件)

John BG
John BG 2016 年 4 月 17 日
編集済み: John BG 2016 年 4 月 17 日
Michael
1 for loop is enough
A=randi([-10 10],5,6) % generate input
B=A(:)' % reshape A into straight line
L=length(B)
C=[]
for k=1:L
v=find(B==max(B)) % in case repeated values
C=[C B(v(1))]
B(v(1))=[]
end
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thanks in advance
John
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Jan
Jan 2016 年 4 月 17 日
The missing pre-allocation is a bad programming style.
John BG
John BG 2016 年 4 月 17 日
編集済み: John BG 2016 年 4 月 24 日
Actually, you are right, there are other ways to build the variable collecting the result, some good habits die hard, like declaring variables before using them.
The 'bad' you mention, why? Because it's going to size some more bytes disk?

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