get matrix in parfor

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vu ngothanh
vu ngothanh 2016 年 4 月 4 日
回答済み: Edric Ellis 2016 年 4 月 12 日
Dear all,
I have this code
result=[]
for m=1:10
for k=1:100
for c=1:50
a=m+k*c;
b=m*k-c;
result=[result;a b];
end
end
end
I try to convert from for to parfor like this
result=[]
for m=1:10
parfor k=1:100
for c=1:50
a=m+k*c;
b=m*k-c;
result=[result;a b];
end
end
end
But there is a problem, "the variable 'result' used a value outside of the loop". I has searched from the site, but i'm not understand about the solution.
How can I fix it.

回答 (1 件)

Edric Ellis
Edric Ellis 2016 年 4 月 12 日
You can't update the parfor reduction variable result inside the inner loop, you need to update it directly in the body of the parfor loop. You can work around this by making a new temporary reduction variable for each iteration of the parfor loop, and then update result once that's complete, like so:
result=[];
for m=1:10
parfor k=1:100
tmp = [];
for c=1:50
a=m+k*c;
b=m*k-c;
tmp=[tmp;a b];
end
result = [result; tmp];
end
end

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