Quantifying pore size distribution for a 3-d image
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Quantifying pore size distribution for a 3-d image?
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Adriana
2023 年 7 月 4 日
編集済み: Image Analyst
2023 年 7 月 4 日
Hello!
Quick question, I've created an aggregate of 1000 spheres with this code:
t = readmatrix('Sim 1.txt');
[xn,yn,zn]=sphere;
i=1;
while i<=1000
for i=i
x=t(i,1);
y=t(i,2);
z=t(i,3);
r=t(i,4);
xi=xn*r+x;
yi=yn*r+y;
zi=zn*r+z;
p(i)=surf(xi,yi,zi);
hold on
i=i+1;
end
end
hold off;
How can I now measure the pore size distribution of my aggregate (1x1000 surface)?
Thank you in advance!
1 件のコメント
Image Analyst
2023 年 7 月 4 日
@Adriana If by "pore" you mean the spheres (like the spheres are voids/holes in a solid volume) then the pore side distribution is just 1000 counts of 1. Since you did not specify an input for sphere, it makes a sphere of radius 1 (diameter of 2).
Conversely, if the volume is void space and the spheres are solid, then you're going to have to define what you mean by a pore. You can get the distance of every pixel to the closest sphere with bwdist and then take the histogram of the distance transform image, if that will help you.
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