Moving average with overlapping windows

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Pierre S.
Pierre S. 2016 年 3 月 25 日
編集済み: Image Analyst 2016 年 3 月 25 日
Hi,
I am looking for an efficient way to compute a moving average with overlapping windows for a matrix X along the first dimension.
A non-efficient solution is the following.
N = 3500000;
X = randn(N,20);
windowSize = 600;
stepSize = 100;
b = (1/windowSize)*ones(1,windowSize);
a = 1;
windowEnd = windowSize:stepSize:N-windowSize+1;
tic
X = filter(b,a,X) ;
X = X(windowEnd) ;
toc
In this solution, I am computing a lot of averages that I am throwing away at the end... This is what I meant by 'non-efficient'.
Thank you in advance for your help.

回答 (1 件)

Image Analyst
Image Analyst 2016 年 3 月 25 日
You can use blockproc() to move a 600x600 window along a matrix in "jumps" of 100. Look at all the arguments and let us know if you can't figure it out.
  2 件のコメント
Pierre S.
Pierre S. 2016 年 3 月 25 日
Thank you for the suggestion. I tried your suggestion. But unfortunately, blockproc() is much slower than filter()... Any other idea? Thanks again.
Image Analyst
Image Analyst 2016 年 3 月 25 日
編集済み: Image Analyst 2016 年 3 月 25 日
You can use conv2() or imfilter(). They are very efficient and fast and highly optimized. However, they don't move in "jumps" of 100, they move by 1 pixel so they do a lot more computations. Whether it will be faster or not is for you to test.
tic;
kernel = ones(101) / 101^2;
blurredImage = conv2(X, kernel, 'same');
elapsedSeconds = toc

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