How to determine the line-number in a file that contains specific statements
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Dear All,
I do have a file that has a line starting with the following statement:
I Need This Line
What I need is to locate the line number of this line and fgetl of the file from beginning to this line(including this line). What should I do? Basically the problem here is the location of the wanted line varies from one file to another so that it makes way too difficult for me to obtain the information I want. Please be advised that I used fopen command to open my input file. Thank you so much
7 件のコメント
KSSV
2016 年 3 月 24 日
You are not opening the file properly....what is fid value? It shall be +ve. Cross check the value of line with your file.
採用された回答
KSSV
2016 年 3 月 24 日
編集済み: KSSV
2016 年 3 月 24 日
Homayoon you may try the following code with the attached txt file.
file = 'Junk.txt' ;
fid = fopen(file,'r') ;
str = 'I Need This Line' ;
for c=1:13
line=strtrim(fgets(fid)) ;
if strcmp(line,str)
iwant = c ;
end
end
fclose(fid) ;
iwant is the line number you wanted.
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その他の回答 (1 件)
Orion
2016 年 3 月 24 日
Hi,
I guess you need something like that.
Assuming you have a .txt file : MyTextFiles.txt, that contains :
ruiez
gjrigj
rjigjri
I Need This Line and the rest of it ?
gjijri
pzepaz
you need a code like that :
% Open and read the content
Myfile = 'MyTextFiles.txt';
fid = fopen(Myfile);
Text = textscan(fid,'%s','delimiter','\n');
Text = Text{1};
fclose(fid);
% pattern to find at the beginning of a line
pattern = 'I Need This Line';
% analyze
found = 0;
for i = 1:length(Text)
if strncmp(Text{i},pattern,length(pattern))
found = i;
break;
end
end
% result
if found
fprintf('pattern at line %d\n',found)
else
fprintf('pattern not found')
end
Of course, you can optimize this code and add a for loop for all the txt files you need to analyse.
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