How to use a loop for an array

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KK
KK 2016 年 3 月 23 日
コメント済み: Image Analyst 2016 年 3 月 26 日
My question is:
I have an array with values ranging from 0 to 200 something, and I need to find the average value for a set range of the data i.e. I need to find the average value for 0 to 1, the average value of the data for 1-2, and so on until it hits the end. I would like to save that information in a new matrix that I can look up later on.
Any help is appreciated.
  2 件のコメント
James Tursa
James Tursa 2016 年 3 月 23 日
What about the boundary points? E.g., if a value is exactly 1, do you want it to be part of the 0-1 average and also the 1-2 average? Or do you want these averages to be mutually exclusive?
KK
KK 2016 年 3 月 23 日
I suppose the range should be greater than the lower bound, less than or equal to the upper bound. I'll have to try out your method.

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採用された回答

Image Analyst
Image Analyst 2016 年 3 月 24 日
If you have the Statistics and Machine Learning Toolbox, you can use grpstats(). It's a single line of code:
% Create sample data
r = 200 * rand(100000, 1);
% Now find means in every integer range.
means = grpstats(r, floor(r))
  4 件のコメント
KK
KK 2016 年 3 月 26 日
Is there a way to save the values used for each mean in an array so that I may apply further operations to that information?
Image Analyst
Image Analyst 2016 年 3 月 26 日
In my code above, means is already an array. Do you mean like an array of those arrays? Like you want a 2D array or an array of structures?

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その他の回答 (1 件)

James Tursa
James Tursa 2016 年 3 月 23 日
編集済み: James Tursa 2016 年 3 月 23 日
Does something like this do what you want?
n = ceil(max(values));
x = bsxfun(@ge,values(:),0:n-1) & bsxfun(@le,values(:),1:n);
averages = sum(bsxfun(@times,values(:),x)) ./ sum(x);
averages(isnan(averages)) = 0;
  1 件のコメント
KK
KK 2016 年 3 月 24 日
The ceil function is pretty cool. I like the idea of using the bsxfun, but how would I be able to calculate the average for the data with a value between 0 and 1, or 1 to 2 (and so on), using this function, for all the values in the array?

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