i have many stations and i want to choose the highest load cost as first and so on
i have six stations with different loads

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Walter Roberson
Walter Roberson 2016 年 3 月 23 日

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[maxload, maxidx] = max(TheLoads)
now maxload stores the value of the largest of TheLoads, and maxidx stores the index within TheLoads, so it tells you which load is largest.

3 件のコメント

ABDULLA RAHIL
ABDULLA RAHIL 2016 年 3 月 23 日
thanks walter but in my case i have 6 stations and 365 days so i need to choose the largest every step , this means that sometimes in the first step the largest in station1 but inthe second in staion6 and so on , how can make it follow all steps and compare between stations and choose the largest ,
Walter Roberson
Walter Roberson 2016 年 3 月 23 日
If TheLoads is a 6 x 365 array, then
[maxload, maxidx] = max(TheLoads);
will have maxload be the maximum per day and maxidx will be the index of the maximum for each day. If your array is 365 x 6 instead, then
[maxload, maxidx] = max(TheLoads, [], 2);
ABDULLA RAHIL
ABDULLA RAHIL 2016 年 3 月 24 日
many thanks for your help Walter

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