setdiff for two matrices

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Mahmoud Zeydabadinezhad
Mahmoud Zeydabadinezhad 2016 年 3 月 18 日
コメント済み: Shuhao Cao 2020 年 5 月 7 日
Hi,
I have two large matrices with the same number of rows but a different number of columns. Let's say A is the larger matrix and B is the smaller one.
Values in each row of the matrix B are a subset of the values of the corresponding row in A. The goal is to have another matrix C which in each row contains the values from the corresponding row of A which are not in corresponding row of B. In other words, I want to use the setdiff(A,B) command, but it should act row by row. Any idea how can I do this without looping?
Thank you!

回答 (2 件)

Guillaume
Guillaume 2016 年 3 月 18 日
編集済み: Guillaume 2016 年 3 月 18 日
I'm afraid there's no other way than looping over the rows either explicitly with a for loop, or with cellfun:
cell2mat(cellfun(@setdiff, num2cell(A, 2), num2cell(B, 2), 'UniformOutput', false))
Note that the above assumes that setdiff returns the same number of elements for each row. Otherwise, you'll have to get rid of the cell2mat call and keep the result as a cell array.
Also, note that an explicit loop may be faster as you wouldn't have to split the inputs into cell arrays of rows.
  1 件のコメント
Mahmoud Zeydabadinezhad
Mahmoud Zeydabadinezhad 2016 年 3 月 18 日
That's unfortunate as looping over for millions of times takes absolute ages to complete.

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Fangjun Jiang
Fangjun Jiang 2016 年 3 月 18 日
setdiff(a,b,'rows') ??
  4 件のコメント
Fangjun Jiang
Fangjun Jiang 2018 年 4 月 24 日
just use setdiff(A(k,:), B(k,:)) and loops through all rows. What is the point to struggle to avoid a loop?
Shuhao Cao
Shuhao Cao 2020 年 5 月 7 日
Because loop is slow for large matrices (especially the sparse matrices).

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