multiple variable function

p=p*(cos((x(:,1))-sin(x(:,2)))
is it
p=p*(cosx1-sinx2)?
what is the difference between?
if its same,then why first one is used?

1 件のコメント

Krishnendu Mukherjee
Krishnendu Mukherjee 2012 年 1 月 29 日
supposey=sin(x(:,i)
if i pass x=[1 2 3 4 5..............n]
will it work?actually things is nt being clear.

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回答 (1 件)

Walter Roberson
Walter Roberson 2012 年 1 月 29 日

0 投票

The first uses trig functions, while the second does not.
The first uses two columns of a variable named "x", while the second uses a variable "cosx1" and another variable "sinx2".
The first is missing a ')', while the second has balanced brackets

4 件のコメント

Krishnendu Mukherjee
Krishnendu Mukherjee 2012 年 1 月 29 日
first one uses two variabe scond one also.cos(x1)-sin(x2)
and cos(x(;1)-sin(x(;2)) what is the difference of uses?if the function is same
Image Analyst
Image Analyst 2012 年 1 月 29 日
You are so sloppy with your typing, that it's probably your main problem. cosx1 is NOT THE SAME as cos(x1). And x(;1) would cause a syntax error while x(:, 1) is perfectly valid.
Krishnendu Mukherjee
Krishnendu Mukherjee 2012 年 1 月 29 日
still thing is nt clear.cos(x1) and cos(x(:,1)) what is the difference of their uses?yes my keybord is very old.that is why all prints hs washed away
Image Analyst
Image Analyst 2012 年 1 月 29 日
You should get a new keyboard - they would be a very cheap fix. cos(x1) is the cosine of the variable x1. x1 is not necessarily the same as x(:,1) unless you said x1 = x(:,1); x1 could be anything at all. It could be pi, it could be 42, or 69 or anything else. Why would you think that x1 should automatically be the same as x(:,1) unless you made it so?

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