Transposing 3 D matrix using permute - how does permute work?
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Ok. So I see how to transpose all the "2D slices" of a 3D matrix on other answers (permute(A, [2 1 3])).
But what does the order vector mean? The 2 means what? The second row, column? Anyone who can explain this, I appreciate it.
Thanks
2 件のコメント
Andrew Newell
2012 年 1 月 24 日
Have you tried "doc permute" yet?
Javed mohd
2018 年 3 月 7 日
Hi, Order vector [1:first dim(row) 2:second dim(col) 3:third dim(Z)] so if you want to transpose rows and columns keeping the same Z, your vector would be [2 1 3]
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その他の回答 (2 件)
James Tursa
2012 年 1 月 25 日
Another way to do 2D slice transposing of an nD Array:
mtimesx(1,A,'t')
You can find mtimesx on the FEX here:
href=""<http://www.mathworks.com/matlabcentral/fileexchange/25977-mtimesx-fast-matrix-multiply-with-multi-dimensional-support</a>>
Ali
2012 年 1 月 24 日
0 投票
2 件のコメント
Walter Roberson
2012 年 1 月 24 日
The third dimension has length 1, and it is left where it is, so the third dimension is 1 afterwards. Trailing 1's from the third dimension onward are not explicitly shown in MATLAB. An array which is 2x2 is also 2x2x1x1x1x1x1 but it would not serve any useful purpose to explicitly display the 250-some-odd trailing subscripts that are all exactly "1".
Andrew Newell
2012 年 1 月 24 日
Each doc page has an option for feedback at the bottom. If you answer "No" to "Was this topic helpful?", you'll get a web form to fill out.
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