Inverse and identity matrix

4 ビュー (過去 30 日間)
nur yusof
nur yusof 2016 年 2 月 22 日
コメント済み: nur yusof 2016 年 2 月 23 日
Given. A=[1 2 3;6 7 8;11 12 13]; B=[4 5 6;9 10 11;14 15 16]; and C=-inv(A)*B/eye(3). And the C matrix is
C =
4 8 8
0 0 -8
0 0 4
The size of C matrix must be 6x3.But I only got 3x3. Why does it happen?

採用された回答

John D'Errico
John D'Errico 2016 年 2 月 22 日
It happens because of the basic rules of those matrix operators.
All of your matrices are 3x3. Both of those binary operations (* and /) between 3x3 matrices result in another 3x3 matrix.
My guess is you have invented in your mind a new rule for the / operator, wherein it becomes a matrix concatenation operator, or something like that. Sorry, but operators have explicit definitions in MATLAB. They follow their defined behaviors, as I would hope they should.
  1 件のコメント
nur yusof
nur yusof 2016 年 2 月 23 日
Ok.Noted.Can you give me one example how to do it?

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeCreating and Concatenating Matrices についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by