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How to display the coordinate of the point in the figure

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T
T 2016 年 1 月 24 日
回答済み: Afshin Aghayan 2019 年 10 月 8 日
The problem is similar to this but I have an x-axis that decreases from 1 to 0 at increments of 0.1 https://www.mathworks.com/matlabcentral/answers/89104-how-to-display-the-coordinate-of-the-point-in-the-figure
for k=1:numel(x)
text(x(k),y(k),['(' num2str(x(k)) ',' num2str(y(k)) ')'])
end
I also need to adjust the window for this but axis won't work because it only applies for increases x-values.
Can someone advise me how to accommodate for these changes?

回答 (3 件)

T
T 2016 年 1 月 24 日
This is the output image of what I'm getting.
You can see the points are not following the curve.

Walter Roberson
Walter Roberson 2016 年 1 月 24 日
The labels are being put into the proper place on the graph. Your third point is at y = -3.something which happens to be outside the range of what you are displaying. That is not the fault of text(), that is because you have told it coordinates that are not on your graph.
  5 件のコメント
Walter Roberson
Walter Roberson 2016 年 1 月 25 日
clf
f = [ 0.99 , 0.77, 0.55, 0.33 ];
y1 = @(f)(-14.2 +1000.0) * f.^(1.02 - 1.0) - 1000.0;
y2 = @(newvariable) (1.02 * (newvariable +1000.0) - 1000.0);
y1f = y1(f);
y2y1f = y2(y1f);
y1_0 = fzero(y1,[0,realmax]);
y2y1_0 = fzero(@(x) y2(y1(x)),[0,realmax]);
h = plot( f , y1f, '--ob', f, y2y1f, '--ok', y1_0, 0, '*r', y2y1_0, 0, '*g' );
set(gca, 'xdir', 'reverse')
XY = [f(:), y1f(:); f(:), y2y1f(:); y1_0, 0; y2y1_0, 0];
labels = cellstr([num2str(XY(:,1)),repmat(', ',size(XY,1),1),num2str(XY(:,2))]);
text(XY(:,1), XY(:,2), labels);
legend(h, {'y1(x)', 'y2(y1(x))', 'y1(x) = 0', 'y2(y1(x)) = 0'}, 'location', 'southwest');
T
T 2016 年 1 月 25 日
The red and green star, what is the purpose of this? It's not a necessary point, I just want to show the 8 points and extrapolate the end of the function as f approaches 0.

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Afshin Aghayan
Afshin Aghayan 2019 年 10 月 8 日
you can use this code for displaying any data in the form of [x, y, f(x,y)] or data with coordinate

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