Error Using Horzcat: Dimensions of matrices being concatenated are not consistent
1 回表示 (過去 30 日間)
古いコメントを表示
I am receiving the following error message:
Error using horzcat
Dimensions of matrices being concatenated are not consistent.
Error in test (line 55)
goodPoints = [goodPoints1, goodPoints2];
where
%
goodPoints1 = find((utcTime >= utcStarts1(jj)) &( utcTime <utcEnds1(jj)));
goodPoints2 = find((utcTime >= utcStarts2(jj)) &( utcTime <utcEnds2(jj)));
goodpoints1 is a 9532x1 double and goodpoints2 is a 8270x1 double
From my understanding this error shows because the two do not have the same number of rows. What alternatives can I use to fix this error? (in the most layman's terms possible!) Thank you for any help!
2 件のコメント
Star Strider
2016 年 1 月 20 日
Your variables ‘goodPoints1’ and ‘goodPoints2’ are vectors of indices, so their order may be important.
What do you want to do with them?
回答 (1 件)
Star Strider
2016 年 1 月 20 日
Put them in a cell array instead (note the curly brackets ‘{}’):
goodPoints = {goodPoints1, goodPoints2};
Cell arrays are a bit more difficult to work with (you have to retrieve the elements of the array to calculate with it, for instance), but are quite useful in storing data such as you want to.
4 件のコメント
Star Strider
2016 年 1 月 20 日
編集済み: Star Strider
2016 年 1 月 20 日
You need to reference either column of ‘goodPoints’ here. For example:
bigDATA(ii, bigDATAstart:(bigDATAstart - 1 +length(goodPoints{1}))) = a(goodPoints{1});
although I have no idea if that is what you want to do.
My pleasure.
参考
カテゴリ
Help Center および File Exchange で Characters and Strings についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!