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Repmat the rows of a matrix

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Luis Isaac
Luis Isaac 2016 年 1 月 20 日
回答済み: Jordan Lui 2020 年 12 月 2 日
Dear;
I would like to efficiently repmat the rows of a matrix to for a new one; For example the matrix:
A=[2 0 0;
0 2 0;
0 0 2;
];
I want to replicate 3 times the rows to form the following matrix:
B=[2 0 0;
2 0 0;
2 0 0;
0 2 0;
0 2 0;
0 2 0;
0 0 2;
0 0 2;
0 0 2;
];
Is there any vectorized way to perform this operation (without using for loops).
Thanks in advance;

回答 (2 件)

Jordan Lui
Jordan Lui 2020 年 12 月 2 日
Be careful with the other answer. It will not work for more general cases. Instead, try this:
numRep = 3;
[r,c] = size(A);
B1 = repmat(A', numRep , 1);
B = reshape(B1, [], r * numRep)';

Star Strider
Star Strider 2016 年 1 月 20 日
This works:
A=[2 0 0;
0 2 0;
0 0 2];
[Ar,Ac] = size(A);
B1 = repmat(A, Ar, 1);
B = reshape(B1, [], size(B1,1))'
B =
2 0 0
2 0 0
2 0 0
0 2 0
0 2 0
0 2 0
0 0 2
0 0 2
0 0 2
  1 件のコメント
Jordan Lui
Jordan Lui 2020 年 12 月 2 日
This solution does not work on an example like this:
A=[2 7 8;
4 2 8;
5 6 2
-1 -1 -1;
];
Using a non square matrix and filling the off diagonals shows the issue. Result will be:
B =
2 4 5
-1 2 4
5 -1 2
4 5 -1
2 4 5
-1 7 2
6 -1 7
2 6 -1
7 2 6
-1 7 2
6 -1 8
8 2 -1
8 8 2
-1 8 8
2 -1 8
8 2 -1
The following solution works:
numRep = 3;
[r,c] = size(A);
B1 = repmat(A', numRep , 1);
B = reshape(B1, [], r * numRep)';

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