Removing a bunch of elements from a 1-D vector?
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I have a large 1-D vector and want to delete ten consecutive elements after the first or second or third one (depending on the signal undergoing processing). For example if my starting vector is x = [1,2,3,4,5,6,7,8,9,10,11........10,000], I want to create another vector which looks like: y = [1,(delete ten elements),12, (delete ten elements),23,(delete ten elements),34,....]. What is the best way to do such an operation?
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Stephen23
2016 年 1 月 22 日
編集済み: Stephen23
2016 年 1 月 22 日
>> X = randi(9,1,23)
X =
3 5 4 4 5 7 8 9 2 4 3 3 2 6 7 5 9 1 8 2 9 4 1
>> start = 3;
>> step = 5;
>> X(start:step:end)
ans =
4 9 2 1 1
Or for the original example:
>> Y = 1:10000;
>> start = 3;
>> step = 11;
>> Y(start:step:end)
ans =
Columns 1 through 14:
3 14 25 36 47 58 69 80 91 102 113 124 135 146
etc
Note that using indexing actually selects the values from the input vector.
その他の回答 (1 件)
Stalin Samuel
2016 年 1 月 19 日
x = [1:1000];
gap = 10;%no of elements to be deleted
y = [min(x):gap+1:max(x)]
2 件のコメント
Stephen23
2016 年 1 月 22 日
編集済み: Stephen23
2016 年 1 月 22 日
@Dheeraj Kapur: this does not actually answer your question, because it does not select elements of the input vector as your original question requests, but instead creates an entirely new vector using the colon operator. This method will fail completely for any vector that is not a sequential sequence of integers with a step of one.
If you want a solution that actually selects elements of the input vector, regardless of their values, then see my answer. My method actually answers your question.
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